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DWG3-15

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DWG3-15

帖子JS » 2005-04-28 00:45

Q15:
If x ≠ 0, then (x + 1/x)2 - (x - 1/x)2 =

A. 1/x
B. x
C. 1
D. 2
E. 4

Ans: E

I try it so many times and always get the answer 4/x. what's wrong with me?? *-) help pls!!
JS
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Re: DWG3-15

帖子DARY » 2005-04-28 01:10

JS \$m[1]:Q15:
If x ≠ 0, then (x + 1/x)2 - (x - 1/x)2 =

A. 1/x
B. x
C. 1
D. 2
E. 4

Ans: E

I try it so many times and always get the answer 4/x. what's wrong with me?? *-) help pls!!


(x + 1/x)^2 - (x - 1/x)^2 才對
展開來算就好了
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帖子JS » 2005-04-28 17:09

Trust me, I am a complete math idiot
So, can you be so kind and tell me what I did wrong here.

(x + 1/x)^2 - (x - 1/x)^2
= (x+1/x –( x-1/x) (x+1/x + x-1/x)
= 2/x . 2x/x
= 4/x

Help!
JS
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帖子DARY » 2005-04-28 20:58

JS \$m[1]:Trust me, I am a complete math idiot
So, can you be so kind and tell me what I did wrong here.

(x + 1/x)^2 - (x - 1/x)^2
= (x+1/x –( x-1/x) (x+1/x + x-1/x)
= 2/x . 2x/x
= 4/x

Help!


問題出在紅色的地方

括號裡面的分母只屬於後面那一項
(x+1/x)=(x)+(1/x)
並不是(x+1)/x,要看清楚喔
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帖子JS » 2005-04-28 22:32

I can't be.... this is ri..... oh my........(fainted)......
JS
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帖子chris8888 » 2007-11-13 10:47

If x ≠ 0, then ((x)+ (1/x))^2 - ((x) - (1/x))^2 =

A. 1/x
B. x
C. 1
D. 2
E. 4

Ans: E

網路上有很多space or sign 很難表示, 最好修改一下題目讓大家在網路上看懂
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