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[問題]GWD 13-20

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[問題]GWD 13-20

文章luluhsiao » 2005-05-29 18:58

Q20:
A certain list consists of 21 different numbers. If n is in the list and n is 4 times the average (arithmetic mean) of the other 20 numbers in the list, then n is what fraction of the sum of the 21 numbers in the list?

Ans : B. 1/6


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luluhsiao
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文章: 13
註冊時間: 2005-05-16 19:59

文章homaru » 2005-05-29 20:29

設另外20個數總和為T
n=4*T/20=T/5
the sum of the 21 numbers =T + T/5=6T/5
n占全部總和的比例=(T/5)/(6T/5)=1/6

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文章: 542
註冊時間: 2004-11-03 10:34
來自: 台北

文章luluhsiao » 2005-05-30 16:57

OK!!謝謝你啦....
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文章: 13
註冊時間: 2005-05-16 19:59

Re: [問題]GWD13-20

文章SELVICHY » 2005-11-06 15:34

[quote="luluhsiao"]Q20:
A certain list consists of 21 different numbers. If n is in the list and n is 4 times the average (arithmetic mean) of the other 20 numbers in the list, then n is what fraction of the sum of the 21 numbers in the list?

Ans : B. 1/6


麻煩一下大家了...謝謝[/quote]

---------------------------------
更快的算法
設20個數字的平均為X,則n=4x, 21個數的總合為24x
4x/24x=1/6
SELVICHY
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文章: 89
註冊時間: 2005-09-13 14:48


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