GWD 00-12

[erica2564]

Q12
A certain dealership has a number of cars to be sold by its salespeople. How many cars are to be sold?

(1) If each of the salespeople sales 4 of the cars, 23 cars will remain unsold.
(2) If each of the salespeople sales 6 of the cars, 5 cars will remain unsold.

A:C

我知道列式子是 N=4a+23 =6b+5
但是接下來就不知道怎麼求了
數學不好，感謝~~

[zazer.lin]

Q12
A certain dealership has a number of cars to be sold by its salespeople. How many cars are to be sold?

(1) If each of the salespeople sales 4 of the cars, 23 cars will remain unsold.
(2) If each of the salespeople sales 6 of the cars, 5 cars will remain unsold.

A:C

我知道列式子是 N=4a+23 =6b+5
但是接下來就不知道怎麼求了
數學不好，感謝~~

小弟猜想erica2564您可能不小心把"N=4a+23 =6b+5"這個式子的變數設錯囉!
在您的式子中 a 和 b 應該都是指 salespeople 的人數, 所以 a = b才對.
所以應該是 N = 4a + 23 = 6a + 5, 由後兩個式子就可以求出 a = 9, 在帶回去就可以求出 N = 59.

[erica2564]

啊哈哈~
我真是阿呆
謝謝zazer.lin 大大的提點阿

[chris8888]

簡單說就是二元一次方程式可解.

假設總共有y台汽車, x個業務員
y = 4x + 23
y = 6x + 5
解連立方程式