請問資充題目一道

[FiscJanet]

這是我在美加補習助教提供的題目，當初沒問題，現在回來看不知為什麼，
覺得條件1與題目不合..?請高手幫忙解答阿！(下禮拜就要考了，現在才在
抱佛腳!)

List S and T consist of the same number of positive integers.
Is the median of the integers in S greater than average
(arithmetic mean) of the integers in T?

(1)The integers in S are consecutive even integers, and the
integers in T are consecutive odd integers.
(2)The sum of the integers in S is greater than the sum of the
integers in T

Ans:C

[agustin]

這是我在美加補習助教提供的題目，當初沒問題，現在回來看不知為什麼，
覺得條件1與題目不合..?請高手幫忙解答阿！(下禮拜就要考了，現在才在
抱佛腳!)

List S and T consist of the same number of positive integers.
Is the median of the integers in S greater than average
(arithmetic mean) of the integers in T?

(1)The integers in S are consecutive even integers, and the
integers in T are consecutive odd integers.
(2)The sum of the integers in S is greater than the sum of the
integers in T

Ans:C

題目是問S數列的中位數 是否會大於T數列的算數平均數 條件給S,T數列有一樣多的數字
單獨看(1) 可能[S]=[6, 8, 10] 而[T]=[1,3,5] 也可以是[21, 23, 25]
無法確定大或小

單獨看(2) 只能知道S,T數列的算數平均數一樣 但是還是不知道[S]的中位數如何 也許[S]=[1,1,1,1,1,1,1,1,8]

合併看得C
因為條件給了S,T也相同多個數
而(1)給了連續偶數 連續奇數 (2)給了平均數一樣
例如[S]=[2,4,6,8] ; [T]=[1,3,5,7]
(注意[T]不可能是別組了 因為被算數平均數給鎖死了)

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