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GWD 07-18

關於 Problem Solving 和 Data Sufficiency 的問題都可以在這邊發表

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GWD 07-18

帖子jerry7271 » 2006-04-03 16:08

查詢過了,沒這題
Q18. Each week, Harry is paid x dollars per hour for the first 30 hours and 1.5x dollars for each additional hour worked that week. Each week, James is paid x dollars per hour for the first 40 hours and 2x dollars for each additional hour worked that week. Last week James worked a total of 41 hours. If Harry and James were paid the same amount last week, how many hours did Harry work last week?

A.35
B.36
C.37
D.38
E.39
答案是D。 不知道怎麼求的?
James 的41小時,amount等於 x+2x
Harry的amount若也要是x+2x,那時數怎麼
會是38呢? 38小時amount應該是x+12x吧?! 求救
過程就一種學習
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jerry7271
中級會員
中級會員
 
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注册: 2005-12-07 14:41

Re: GWD 07-18

帖子stwang » 2006-04-03 18:37

jerry7271 \$m[1]:查詢過了,沒這題
Q18. Each week, Harry is paid x dollars per hour for the first 30 hours and 1.5x dollars for each additional hour worked that week. Each week, James is paid x dollars per hour for the first 40 hours and 2x dollars for each additional hour worked that week. Last week James worked a total of 41 hours. If Harry and James were paid the same amount last week, how many hours did Harry work last week?

A.35
B.36
C.37
D.38
E.39
答案是D。 不知道怎麼求的?
James 的41小時,amount等於 x+2x
Harry的amount若也要是x+2x,那時數怎麼
會是38呢? 38小時amount應該是x+12x吧?! 求救


Jame事前40小時每小時領X 所以41小時是40X+2X=42X
Harry前30小時每小時領X
所以就是(42X-30X)/1.5=8 30+8=38 :laugh
stwang
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注册: 2005-01-14 17:08

帖子jerry7271 » 2006-04-04 08:45

知道了...感謝!
真的要細心一點!!
過程就一種學習
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jerry7271
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中級會員
 
帖子: 83
注册: 2005-12-07 14:41


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