Prep-T2 DS Q120

[hsinyang]

120.

If n is the product of the least and the greatest of 6 consecutive integers, what is the value of n ?

(1) The greatest of the 6 consecutive integers is 20.

(2) The average (arithmetic mean) of the 6 consecutive integers is 17.5.

Ans. D
請問這題要如何解呢?

[amazingslim]

120.

If n is the product of the least and the greatest of 6 consecutive integers, what is the value of n ?

(1) The greatest of the 6 consecutive integers is 20.

(2) The average (arithmetic mean) of the 6 consecutive integers is 17.5.

Ans. D
請問這題要如何解呢?

n是連續整數中最大及最小乘積
六個連續整數
設a, a+1, .......a+5
(1)最大是20
a+5=20，所以可以得知n
(2)a+(a+1)+(a+2)+.....(a+5)=6*17.5
列出式子，a不用算出來(因為一定有解)，即可得知n

所以答案為D

[Huang Hsin-Yi]

請問若是
a,a+2,a+4,a+6,a+8,a+10這樣的數列 英文怎樣說