Deprecated: preg_replace(): The /e modifier is deprecated, use preg_replace_callback instead in /home/formosam/public_html/phpBB3/includes/bbcode.php on line 112

Deprecated: preg_replace(): The /e modifier is deprecated, use preg_replace_callback instead in /home/formosam/public_html/phpBB3/includes/bbcode.php on line 112

Deprecated: preg_replace(): The /e modifier is deprecated, use preg_replace_callback instead in /home/formosam/public_html/phpBB3/includes/bbcode.php on line 112
FormosaMBA 傷心咖啡店 • 檢視主題 - PP1-203-DS

PP1-203-DS

關於 Problem Solving 和 Data Sufficiency 的問題都可以在這邊發表

版主: shpassion, Traver0818

PP1-203-DS

文章pimi » 2007-12-09 13:06

203. 19582-!-item-!-187;#058&012370
What is the remainder when the positive integer x is divided by 6?

(1) When x is divided by 2, the remainder is 1; and when x is divided by 3, the remainder is 0.

(2) When x is divided by 12, the remainder is 3.

Ans: D

我選擇B, 因為題目說x=6a+r, (2)說x=12b+3, 可以把(2)整理成6(2b)+3, 就可以得到餘數是3

但是為何A也可以解出答案呢??? :^)
pimi
高級會員
高級會員
 
文章: 388
註冊時間: 2005-01-21 14:50

Re: PP1-203-DS

文章amazingslim » 2007-12-10 21:19

pimi \$m[1]:203. 19582-!-item-!-187;#058&012370
What is the remainder when the positive integer x is divided by 6?

(1) When x is divided by 2, the remainder is 1; and when x is divided by 3, the remainder is 0.

(2) When x is divided by 12, the remainder is 3.

Ans: D

我選擇B, 因為題目說x=6a+r, (2)說x=12b+3, 可以把(2)整理成6(2b)+3, 就可以得到餘數是3

但是為何A也可以解出答案呢??? :^)


之前看過大陸人提供這種問題的算法
(1)設x=2a+1=3b
找數字代進去公式相等,a.b最小均為1,so x=3(也就是說餘數為3)
當a=4,b=3,x=9(但是被6除,餘數還是3)
所以x=6c+3(6為2跟3最小公倍數)
amazingslim
中級會員
中級會員
 
文章: 147
註冊時間: 2007-08-11 17:14

文章pimi » 2007-12-19 13:30

感激大大回覆

想請問設x=2a+1=3b, 再代數字, 感覺不是很保險, 畢竟考試也沒有太多時間讓我們帶太多數字, 而代的數字樣本數不夠, 又擔心會有啥例外出現 > <

像B選項很明顯, 不需要透過帶數字, 就可以看出答案, 但A~~~~
哀哀
請大大指導~
pimi
高級會員
高級會員
 
文章: 388
註冊時間: 2005-01-21 14:50

文章scottkidd » 2007-12-19 17:26

題目要知道x除以6的餘數...
(1) When x is divided by 2, the remainder is 1; and when x is divided by 3, the remainder is 0.

6=2*3
可以知道若x被6整除,則需要x同時是2和3的倍數
但(1)說x是3的倍數,但是x被2除卻餘1(這可以推x是奇數),
這樣有兩個方向可以想:
(a)被3整除,除2卻餘1,可以推得餘數一定是2+1=3
OR (b)直接找是3的倍數同時是奇數的代看看就可以知道了
scottkidd
初級會員
初級會員
 
文章: 58
註冊時間: 2006-04-12 12:13


回到 GMAT MATH 考區

誰在線上

正在瀏覽這個版面的使用者:沒有註冊會員 和 23 位訪客

cron