GWD 04-17

[nana]

Q17:
The number of defects in the first five cars to come through a new production line are 9, 7, 10, 4, and 6, respectively. If the sixth car through the production line has either 3, 7, or 12 defects, for which of theses values does the mean number of defects per car for the first six cars equal the median?


I. 3
II. 7
III. 12


A. I only
B. II only
C. III only
D. I and III only
E. I, II, and III

答案是D
還搞不清楚中數在搞什麼..... :(
要依照大小順序排嗎

[homaru]

是低,要按照大小順序排
I. 3 --> 3,4,6,7,9,10 (中位數(6+7)/2=6.5, 平均數=6.5)
II. 7 --> 4,6,7,7,9,10 (中位數7, 平均數7.17)
III. 12--> 4,6,7,9,10,12 (中位數(7+9)/2=8, 平均數=8)
所以答案D

[nana]

多謝homaru詳解
但我還想問一下中數跟中位數有差嗎
我一直以為中數和中位數其中一個要排大小
考題都說the median讓我霧煞煞了

[micht]

中數就是 medium 要排列才看得出中數是哪一個

如果是偶數個數 中位數是中間兩數的平均
如果是奇數個數 中位數是中間那一個

[法法]

The number of defects in the first five cars to come through a new production line are 9, 7, 10, 4, and 6, respectively. If the sixth car through the production line has either 3, 7, or 12 defects, for which of theses values does the mean number of defects per car for the first six cars equal the median?

可否協助解釋~~題意不甚懂~~謝謝~~

[yuying]

新生產線5台車分別有 9, 7, 10, 4, 6個缺點(defects), 如果第6台車的缺點是3,7或12個, 第6台車有一個缺點數,會使6個數滿足平均數=中位數

這樣可以理解嗎? 我忘了defect 在品管理的中文怎麼翻....缺陷? 缺失? ..^^;;

[ai12345]

還是搞不清楚答案為何是D.
可否請前輩再詳加說明！THANKS.

[aerobert]

生產線前五台下線車中的缺點數分別是9、7、10、4、6，當第六台車下線時缺點數是3、7或12個，而第六台車的缺點是多少時，這六台車的缺點平均數會等於缺點中位數。
算中位數時需將數據由大到小排列
偶數個數據時中位數為中間兩個的平均
奇數個數據時中位數為中間那一個