PP-Test2-DS-166

[chris8888]

166. 16673-!-item-!-187;#058&011115
If the prime numbers p and t are the only prime factors of the integer m, is m a multiple of p2t ?

(1) m has more than 9 positive factors.

(2) m is a multiple of p3.

[Huang Hsin-Yi]

問 m是否為p^2t的倍數?

(1)得知 m=p*t*a*b*c*d*e*f*g/P^2t 約分後,分母還有個p,但不知 剩下那7個factors有無 p的倍數
insufficient

(2)得知m=p*p*p/p^2t 約分後,剩 p/t. we know p and t are prime numbers
所以 互不能整除

所以 m一定不是 p^2t的倍數
sufficient