[問題]GWD25-23

[mingwhale]

Q23.
At a fruit stand yesterday, the price of each apple was $0.10 more than the price of each orange. What was the total revenue from the sale of oranges at the fruit stand yesterday?
(1) The number of oranges sold at the fruit stand
yesterday was 5 more than the number of
apples.
(2) The total revenue from the sale of apples
at the fruit stand yesterday was $15.00

答案：C
又是一個不懂，媽呀~~

[chour]

我覺得答案是E

蘋果每個貴橘子$0.1,求昨天橘子一共賣了多少錢?
設橘子一個P元,蘋果P+0.1元
橘子賣了Q個,蘋果賣R個
(1)橘子比蘋果多賣5個-->Q=R+5,不充分
(2)兩種東西總收入15元-->PQ+(P+0.1)*R=15,不充分
一起考慮,P(R+5)+(P+0.1)*R=15,仍然不充分

[mingwhale]

我自己也是選E，謝謝妳加強了我的信心^^

[skull]

我也是選E, 兩個條件加起來 未知數仍求不出

還是有人可以用以下程式解出 P*Q為多少
(P+0.1)(Q-5)=15

[Penny Lee]

I vote for E.

[chris8888]

At a fruit stand yesterday, the price of each apple was $0.10 more than the price of each orange. What was the total revenue from the sale of oranges at the fruit stand yesterday?
(1) The number of oranges sold at the fruit stand
yesterday was 5 more than the number of
apples.
(2) The total revenue from the sale of apples
at the fruit stand yesterday was $15.00

根據題目 : 假設orange price = x, apple price = x+0.1

根據一, 假設apple quantity = a, orange quantity = a + 5
x * (a+5) + (x+0.1) * a <== 解不出

根據二, 假設apple quantity =a , (x+0.1) * a = 15, 假設orange quantity = b
15 + b * x =? <== 解不出

(1) + (2),
x * (a+5) + (x+0.1) * a = T (Total Revenue)
15 + x * (a+5) = T (Total Revenue) <== 應該試算不出來, 三個variables, two equations

答案E被推出, 各位大大, any ideas ?