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[問題]GWD25-18

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[問題]GWD25-18

文章magic » 2006-11-03 01:06

Q18
An equal number of desks and bookcases are to be placed
along a library wall that is 15 meters long. Each desk is
2 meters long, and each bookshelf is 1.5 meters long. If
the maximum possible number of desks and bookcases
are to be placed along the wall, then the space along the
wall that is left over will be how many meters long?

A.0.5
B.1
C.1.5
D.2
E.3

答案是B
請問怎麼算的阿
我算出來是B和D都有可能耶
magic
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文章: 93
註冊時間: 2006-04-30 23:46

Re: [問題]GWD25-18

文章kwtluck » 2006-11-03 12:34

題目說equal number of desks and bookcases
所以假設desks and bookcases 各有x張
則2x+1.5x=15 => 3.5x=15 => x=4 代回
2(4)+1.5(4)=14 => 15-14=1
kwtluck
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文章: 121
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文章CherrieLi » 2007-11-19 22:23

請問題目哪裡有說 equal number 呢? 不是 maximum possible number 嗎?

我算出來是沒有間距耶....就是0....

當2m desk有3張, 1.5m的 bookshelf有6張, 加起來剛好15m....
CherrieLi
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文章: 125
註冊時間: 2007-06-14 21:37

文章chris8888 » 2007-12-01 01:30

An equal number of desks and bookcases are to be placed
along a library wall

本題有點考GMAT verbal的意涵, An equal number of desks and bookcases are <== 請注是它是用plural verb, 所以解釋為desks的數目, bookcases的數目, 而此數目相等, 他用一個形容詞搞定, an equal number of N1 and N2, 翻譯為 : 書桌數目和書架數目一樣, 皆被放在 ...
一般用法是a number of + N <== 表示很多個N這個東西
頭像
chris8888
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文章: 444
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