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[問題]GWD28-30

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[問題]GWD28-30

帖子kaijen » 2007-09-04 00:52

Q30:
A rectangular photograph is surrounded by a border that is 1 inch wide on each side. The total area of the photograph and the border is M square inches. If the border had been 2 inches wide on each side, the total area would have been (M + 52) square inches. What is the perimeter of the photograph, in inches?

A. 34
B. 36
C. 38
D. 40
E. 42


Ans: D
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kaijen
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帖子kaijen » 2007-09-04 00:57

設長=X 寬=Y 求周長2(X+Y)
(X+1)(Y+1)=M
(X+2)(Y+2)=M+52
展開得
XY+ (X+Y)+1=M
XY+2(X+Y)+4=M+52
兩式相減
X+Y=49 得周長2(X+Y)=98
請問我哪裡算錯了? 謝謝
Kevin Wang
Candidate for MBA, Class of 2011
Duke University, The Fuqua School of Business
kaijen.wang@fuqua.duke.edu
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帖子dibert8 » 2007-09-04 14:44

外框面積 M = (X+2)*(Y+2) = XY + 2*(X+Y) + 4
M + 52 = (X+4)*(Y+4) = XY + 4*(X+Y) + 16
=> 52 = 2*(X+Y) + 12
=> 40 = 2*(X+Y)
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帖子livory » 2007-12-21 15:30

這題意思不太懂耶!
有人可以幫忙解釋一下嘛?
謝謝!
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