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There are 8 magazines lying on a table; 4 are fashion magazines and the other 4 are sports magazines. If 3 magazines are to be selected at random from the 8 magazines, what is the probability that at least one of the fashion magazines will be selected?
The probability that at least one of the fashion magazines will be selected = 1 - the probability that none of the fashion magazine is selected
所以答案為 1 - C4,3 / C8,3 = 1 - 1/14 = 13/14.
ps1. Cm,n 表 m 取 n
ps2. 請問答案對嗎?