Deprecated: preg_replace(): The /e modifier is deprecated, use preg_replace_callback instead in /home/formosam/public_html/phpBB3/includes/bbcode.php on line 112

Deprecated: preg_replace(): The /e modifier is deprecated, use preg_replace_callback instead in /home/formosam/public_html/phpBB3/includes/bbcode.php on line 112

Deprecated: preg_replace(): The /e modifier is deprecated, use preg_replace_callback instead in /home/formosam/public_html/phpBB3/includes/bbcode.php on line 112
FormosaMBA 傷心咖啡店 • 查看主题 - PP-T1-DS50

PP-T1-DS50

關於 Problem Solving 和 Data Sufficiency 的問題都可以在這邊發表

版主: shpassion, Traver0818

PP-T1-DS50

帖子slin0717 » 2008-02-19 22:06

50. 4230-!-item-!-187;#058&003784

A construction company was paid a total of $500,000 for a construction project. The company's only costs for the project were for labor and materials. Was the company's profit for the project greater than $150,000 ?

(1) The company's total cost was three times its cost for materials.

(2) The company's profit was greater than its cost for labor.

答案:C

能請版上的先進指點一下嗎?謝謝
slin0717
新手會員
新手會員
 
帖子: 7
注册: 2007-07-06 11:33

帖子amyliang » 2008-02-20 03:04

based on the question, C=L+M, Pro=Rev-Cost=Pro=500k-(L+M)
(1)C=3M=M+L => Pro=500k-3M insufficient
(2)P=R-C>L => Pro=500k-C>L insufficient

(1)+(2)
P=500k-C=500K-3M>L (L=2M)
M<100
P=500k-3M=200 which is greater than 150K
年輕的時侯真該多讀點書......
amyliang
中級會員
中級會員
 
帖子: 146
注册: 2006-01-13 20:13

帖子slin0717 » 2008-02-24 21:07

謝謝...
slin0717
新手會員
新手會員
 
帖子: 7
注册: 2007-07-06 11:33

帖子chencraig0227 » 2008-07-01 15:54

amyliang \$m[1]:based on the question, C=L+M, Pro=Rev-Cost=Pro=500k-(L+M)
(1)C=3M=M+L => Pro=500k-3M insufficient
(2)P=R-C>L => Pro=500k-C>L insufficient

(1)+(2)
P=500k-C=500K-3M>L (L=2M)
M<100
P=500k-3M=200 which is greater than 150K


請問 M<100, 又L=2M, 所以 L<200吧! 怎麼會直接導出P=...=200?
头像
chencraig0227
中級會員
中級會員
 
帖子: 236
注册: 2007-08-09 22:53

帖子canadacom_orig » 2008-07-01 17:19

應該是p>200...

他只是把p最小的可能寫出來

p最小趨近於200 但大於200
canadacom_orig
新手會員
新手會員
 
帖子: 7
注册: 2008-01-04 08:56

帖子chencraig0227 » 2008-07-01 23:58

canadacom \$m[1]:應該是p>200...

他只是把p最小的可能寫出來

p最小趨近於200 但大於200


不好意思! 這邊我轉不出來...
M<100 所以 2M<200
那麼P<L, L=2M 所以 P<2M (2M<200)
這樣P應該要<200阿? 怎麼會大於呢??
头像
chencraig0227
中級會員
中級會員
 
帖子: 236
注册: 2007-08-09 22:53

帖子larry.tw » 2008-07-02 00:49

弄簡單一點給你參考參考

(2)其實應該是 P>L (profit > Labor cost)
(1) + (2)
P > L
=>500-3M > L
=>500-3M >2M
=>5M < 500
=> M<100

又P=500-3M
把M<100代進上面的式子(隨便代99,98)應該很容易看出來,p永遠大於200,充分

看到你的問題了!!!不是P<L喔 ^^""
larry.tw
中級會員
中級會員
 
帖子: 155
注册: 2007-01-10 16:45

帖子chencraig0227 » 2008-07-02 11:10

感激! 做數學腦子真的容易打結!
头像
chencraig0227
中級會員
中級會員
 
帖子: 236
注册: 2007-08-09 22:53


回到 GMAT MATH 考區

在线用户

正在浏览此版面的用户:没有注册用户 和 7 位游客