GWD2-12

[uneverno]

Ｑ１２
Ａ　can manufacturing company has 5 identical machines, each of which produces cans at the same constant rate. How many cans will all 5 machines produce running simultaneously for z hours?

(1) Running simultaneously, 3 of the machines produce 72000 cans in 2z hours.
(2) Running simultaneously, 2 of the machines produce 24000 cans in z hours.

答案：Ｄ

[汪汪北鼻]

(1) Running simultaneously, 3 of the machines produce 72000 cans in 2z hours.

1)sufficient, (72000/2z)/3=12,000/z, for all 5 machines produce running simultaneously for z hours is 12,000*5/z

(2) Running simultaneously, 2 of the machines produce 24000 cans in z hours. 2)

2)Also sufficient ,(24,000/z)/2=12,000/z, for all 5 machines produce running simultaneously for z hours is 12,000*5/z

thus the answer is D

[uneverno]

謝謝你的解答~可是我想請問一下"12,000/z" 指得是z小時造出12000個cans嗎?
那為什麼後面是"12,000*5/z" 不直接*5就好了呢?
抱歉ㄛ 腦筋比較鈍>"<

[汪汪北鼻]

謝謝你的解答~可是我想請問一下"12,000/z" 指得是z小時造出12000個cans嗎?
那為什麼後面是"12,000*5/z" 不直接*5就好了呢?
抱歉ㄛ 腦筋比較鈍>"<

12,000/z是指一台z小時的產量，現在有5台所以*5
如果你指一台z小時造出12000個cans，那5台就直接*5了
結果都一樣的